25/169=b^2

Solution for 25/169=b^2 equation:

25/169=b^2

We move all terms to the left:

25/169-(b^2)=0

We add all the numbers together, and all the variables

-1b^2+25/169=0

We multiply all the terms by the denominator


-1b^2*169+25=0

Wy multiply elements

-169b^2+25=0

a = -169; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-169)·25
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-130}{2*-169}=\frac{-130}{-338}
=5/13
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+130}{2*-169}=\frac{130}{-338}
=-5/13
$